Three particles having their changes in the ratio of `1 : 3 : 5` produce the same spot on the screen in Thomson's experiment . Their respective masses are in the ratio of

Options

A. ` 5 : 3 : 1`
B. `3 : 1 : 5`
C. `1 : 3 : 5`
D. `5 : 1 : 3`

Answer

C

Explanation

Since spot is same , hence `( e)/(m)` should be same i.e.,
As `q_(1) : q_(2) : q_(3) = 1 : 3 : 5`. Hence `m_(1) : m_(2) : m_(3) = 1 : 3 : 5`