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Light from a hydrogen tube is incident o...

Light from a hydrogen tube is incident on the cathode of a photoelectric cell the work function of the cathode surface is `4.2 eV`. In order to reduce the photo - current to zero the voltage of the anode relative to the cathode must be made

A

`- 4.2 V`

B

` - 9.4 V`

C

`- 17.8 V`

D

`+ 9.4 V`

Text Solution

Verified by Experts

The correct Answer is:
B
`E = W_(0) + eV_(0)`
For hydrogen atom , `E = + 13.6 eV`
`:. + 13.6 = 4.2 + eV_(0)`
`rArr V_(0) = ((13.6 - 4.2) eV)/( e ) = 9.4 V`
Potential at anode ` = - 9.4 V`
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