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In order to coincide the parabolas forme...

In order to coincide the parabolas formed by singly ionized ions in one spectrograph and doubly ionized ions in the other Thomson's mass spectrograph , the electric fields and magnetic fields are kept in the ratios `1 : 2` and `3 : 2` respectively . Then the ratio of masses of the ions is

A

`3 : 4`

B

`1 : 3`

C

`9 : 4`

D

None of thses

Text Solution

Verified by Experts

The correct Answer is:
C
Using `Z^(2) = k((q)/(m)) y` , where `k = (B^(2) LD)/(E )`
For parabolas to coincide in the two photographs , the
`(kq)/(m)` should be same for the two cases . Thus ,
`(B_(1) ^(2) LD e)/(E_(1) m_(1)) = (B_(2)^(2) LD ( 2e))/( E_(2) m_(2))`
` rArr (m_(1))/(m_(2)) = ((B_(1))/(B_(2)))^(2) xx ((E_(2))/(E_(1))) xx (1)/(2) = (9)/(4) xx (2)/(1) xx (1)/(2) = (9)/(4)`
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Knowledge Check

  • Electric field and magnetic field in Thomson mass spectrograph are applied

    A
    Simultaneously, perpendicular
    B
    Perpendicular but not simultaneously
    C
    Parallel but no simultaneously
    D
    Parallel simultaneously

  • Two particles having same charge and KE enter at right angles into the same magnetic field and travel in circular paths of radii 2 cm and 3cm respectively. The ratio of their masses is .

    A
    `2:3`
    B
    `3:2`
    C
    `4:9`
    D
    `9:4`

  • In a parabola spectrograph, the velocities of four positive ions P,Q,R and S are v_(1),v_(2),v_(3) and v_(4) respectively

    A
    `v_(1) gtv_(2)gtv_(3)gtv_(4)`
    B
    `v_(1) lt v_(2) lt v_(3) lt v_(4)`
    C
    `v_(1)=v_(2)=v_(3)=v_(4)`
    D
    `v_(1) lt lt v_(2) gt v_(3) lt v_(4)`

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