In the following diagram if `V_(2) gt V_(1)` then

Options

A. `lambda_(1) = sqrt(lambda_(2))`
B. `lambda_(1) lt lambda_(2)`
C. `lambda_(1) = lambda_(2)`
D. `lambda_(1) gt lambda_(2)`

Answer

D

Explanation

`because V_(0) = ((h)/(e )) v - ((W_(0))/( e ))`. From the graph `V_(2) gt V_(1)`
`rArr (hv_(2))/( e ) - (W_(0))/( e) gt ( hv_(1))/( e ) - (W_(0))/( e) rArr v_(2) gt v_(2)`
`rArr lambda_(1) gt lambda_(2) ( as lambda prop (1)/(V))`