The correct graph between the maximum energy of a photoelectron and the inverse of wavelength of the incident radiation is given by the curve

Options

A. `A`
B. `B`
C. `C`
D. None of the above

Answer

A

Explanation

`K_(max) = hv - hv_(0) = (hc)/(lambda) - ( hc)/(lambda_(0))` i.e., graph between `K_(max)` and `(1)/(lambda)` will be straight line having slope `(hc)` and intercept `(hc)/(lambda_(0)) on KE axis`.