For photoelectric emission from certain metal the cut - off frequency is `v`. If radiation of frequency `2 v` impinges on the metal plate , the maximum possible velocity of the emitted electron will be (`m` is the electron mass).

Options

A. `sqrt((hv)/(( 2 m)))`
B. `sqrt((hv)/(m))`
C. `sqrt((2 hv)/(m))`
D. `2 sqrt((hv)/(m))`

Answer

C

Explanation

`(1)/(2) m upsilon_(max)^(2) = h 2 v - hv rArr upsilon_(max) = sqrt((2 hv)/(m))`