The frequency of incident light falling on a photosensitive metal plate is doubled, the K.E of the emitted photo-electrons is

Options

A. double the earlier value
B. unchanged
C. more than doubled
D. less than doubled

Answer

C

Explanation

`E = W_(0) + K_(max) rArr K_(max) = E - W_(0) = hv - W_(0)`
`rArr K_(1) = hv - W_(0)` and `K_(2) = 2hv - W_(0)`
`rArr K_(2) gt 2K_(1)`