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In a Millikan's oil drop experiment the ...

In a Millikan's oil drop experiment the charge on an oil drop is calculated to be `16.35 xx 10^(-19) C`. The number of excess electrons on the drop is

A

`3.9`

B

`4`

C

`4.2`

D

`6`

Text Solution

Verified by Experts

The correct Answer is:
B
`n = (Q)/(e) = (6.35 xx 10^(-19))/(1.6 xx 10^(-19)) ~~4`
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Knowledge Check

  • In Millikan's oil drop experiment, we make use of:

    A
    Ohm's law
    B
    Ampere's law
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    Stoke's law
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    em

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    electric chage depends on velocity
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    electric charge is quantised

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