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In Thomson experiment of finding e//m fo...

In Thomson experiment of finding `e//m` for electrons, been of electron is replaced by that of muons (particle with same charges as of electrons but mass `208` times that of electrons). No deflection condition in this case satisfied if

A

`B` is increased `208` times

B

`E` is increased `208` times

C

`B` is increased `14.4` times

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
In the condition of no deflection `(e)/(m) = (E^(2))/(2VB^(2)) rArr` If `m` is increased by `208` times then `B` should be increased `sqrt(208) = 14.4` times.
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Knowledge Check

  • In Thomson experiment of finding e/m for electrons beam of electrons is replaced by that of muons (particle with same charge as of electrons but mass 208 times that of electrons) no deflection condition in this case satisfied if

    A
    B is increased 208 times
    B
    E is increased 208 times
    C
    B is increased 14.4 times
    D
    none of the above

  • In Thomson's method of determining e/m of electrons

    A
    Electric and magnetic fields are parallel to electrons beam
    B
    Electric and magnetic fields are perpendicular to each other and perpendicular to electrons beam
    C
    Magnetic field is parallel to the electrons beam
    D
    Electric field is parallel to the electrons beam

  • A particle having the same charge and 200 times greater mass than that of electron is

    A
    Positron
    B
    Proton
    C
    Neutrino
    D
    Meson

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