An alpha-particle is accelerated through...

An `alpha`-particle is accelerated through a.p.d of `10^(6)` volt the `K.E.` of particle will be

`8 MeV`

`4MeV`

`2MeV`

`1 MeV`

Text Solution

Verified by Experts

The correct Answer is:

`K = Q. DeltaV = (2e) xx 10^(6) V = 2 xx 10^(6) eV = 2MeV`

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