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In an electron gun, the electrons are ac...

In an electron gun, the electrons are accelerated by the potential `V`. If the `e` is the charge and `m` is the mass of the electron, then the maximum velocity of these electrons will be

A

`(2eV)/(m)`

B

`sqrt((2eV)/(m))`

C

`sqrt((2m)/(eV))`

D

`(V^(2))/(2em)`

Text Solution

Verified by Experts

The correct Answer is:
B
`eV = (1)/(2) mv^(2) rArr v^(2) = (2eV)/(m) rArr v = sqrt((2eV)/(m))`
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