If scattering particles are `56` for `90^(@)` angle than this will be at `60^(@)` angle

Options

A. `224`
B. `256`
C. `98`
D. `108`

Answer

A

Explanation

According to scattering formula
`N prop (1)/(sin^(4) (theta//2)) rArr (N_(2))/(N_(1)) = [(sin(theta_(1)//2))/(sin(theta_(2)//2))]^(4)`
`rArr (N_(2))/(N_(1)) = [sin((90^(@))/(2))/(sin((60^(@))/(2)))]^(4) = [(sin45^(@))/(sin30^(@))]^(4)`
`rArrN_(2) = (sqrt(2))^(4)xxN_(1) = 4 xx 56 = 224`