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The energy required to knock out the ele...

The energy required to knock out the electron in the third orbit of a hydrogen atom is equal to

A

`13.6 eV`

B

`+(13.6)/(9)eV`

C

`-(13.6)/(9)eV`

D

`-(3)/(13.6)eV`

Text Solution

Verified by Experts

The correct Answer is:
B
Energy required to knock out the eleectron in the nth
orbit `= + (13.6)/(n^(2)) eV rArr E_(3) = + (13.6)/(9)eV`.
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