Ionization potential of hydrogen atom is `13.6 V`. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy `12.1 eV`. The spectral lines emitted by hydrogen atoms according to Bohr's theory will be

Options

A. one
B. two
C. three
D. four

Answer

C

Explanation

Final energy of elctron `= - 13.6 + 12.1 = - 1.51 eV`,
which correcponds to third level i.e `n = 3`.
Hence number of spectral lines emitted
`= (n(n - 1))/(2) = (3(3 - 1))/(2) = 3`