In any Bohr orbit of the hydrogen atom, the ratio of kinetic energy to potential eenrgy of the electron is

Options

A. `1//2`
B. `2`
C. `-1//2`
D. `-2`

Answer

C

Explanation

`K.E. = (kZe^(2))/(2r)` and `P.E. = - (kZe^(2))/(r ), :. (K.E.)/(P.E.) = - (1)/(2)`