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An electron in the n = 1 orbit of hydrog...

An electron in the `n = 1` orbit of hydrogen atom is bound by `13.6 eV`energy is required to ionize it is

A

`13.6 eV`

B

`6.53 eV`

C

`5.4 eV`

D

`1.51 eV`

Text Solution

Verified by Experts

The correct Answer is:
A
Ionization energy = Binding energy.
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The energy of an electron in the first orbit of hydrogen atom is -13.6 eV. The energy of electron in the 4th orbit is_______ eV.

Assume that the charge of an electron is 1.6times10^(-19) coulomb and the energy of the first orbit of hydrogen atom is -13.6 eV. If the energy required to excite the ground state electron of hydrogen atom to the first excited state, is expressed as y times10^(-19)J per atom, what is the value of y ?

Knowledge Check

  • An electron in the n = 1 orbit of hydrogen atom is bound by 13.6 eV . If a hydrogen atom I sin the n = 3 state, how much energy is required to ionize it

    A
    `13.6 eV`
    B
    `4.53 eV`
    C
    `3.4 eV`
    D
    `1.51 eV`

  • The ionization energy of the electron in the lowest orbit of hydrogen atom is 13.6 eV. The energies required in eV to remove an electron from three lowest energy orbits of hydrogen atom respectively are

    A
    `13.6, 6.8, 8.4`
    B
    `13.6,10.2, 3.4`
    C
    `13.6, 27.2, 40.8`
    D
    `13.6, 3.4, 1.51`

  • The binding energy of the electron in the lowest orbit of the hydrogen atom is 13.6 ev. The energies required in eV to remove an electron from three lowest orbits of the hydrogen are-

    A
    13.6,6.8,8.4 eV
    B
    13.6, 10.2, 3.4 eV
    C
    13.6, 27.2 40.8 eV
    D
    13.6,3.4,1.5 eV

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