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The energy of a hydrogen atom in its gr...

The energy of a hydrogen atom in its ground state is `-13.6 eV`. The energy of the level corresponding to the quantum number `n = 2` (first excited state) in the hydrogen atom is

A

`-2.72 eV`

B

`-0.85 eV`

C

`-0.54 eV`

D

`-3.4 eV`

Text Solution

Verified by Experts

The correct Answer is:
D
`E_(n) = (-13.6)/(n^(2)) = (-13.6)/(4) = - 3.4 eV`
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