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Minimum excitation potential of Bohr's f...

Minimum excitation potential of Bohr's first orbit hydrogen atom is

A

`13.6 V`

B

`3.4 V`

C

`10.2 V`

D

`3.6 V`

Text Solution

Verified by Experts

The correct Answer is:
C

Excitation potential `= ("Excitation energy")/(e)`
Minimum excitation energy corresponds to excitation from `n = 1` to `n = 2`
`:.` Minimum excitation energy in hydrogen atom
`= - 3.4 -(-13.6) = + 10.2 eV`
so minimum excitation potential `= 10.2 eV`
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