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When an electron in hydrogen atom is exc...

When an electron in hydrogen atom is excited, from its `4`th to `5`the stationary orbit, the change in angular momentum of electron is (Planck's constant: `h = 6.6 xx 10^(-34) J-s`)

A

`4.16 xx 10^(-34) J-s`

B

`3.32 xx 10^(-34) J-s`

C

`1.05 xx 10^(-34) J-s`

D

`2.08 xx 10^(-34) J-s`

Text Solution

Verified by Experts

The correct Answer is:
C

Change in the angular momentum
`Delta L = L_(2) - L_(1) = (n^(2)h)/(2pi) - (n_(1)h)/(2pi) rArr DeltaL = (h)/(2pi) (n_(2) - n_(1))` ltbegt `= (6.6 xx 10^(-34))/(2 xx 3.14) (5 - 4) = 1.05 xx 10^(-34) J-s`
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