In a hydrogen atom, the distance between the electron and proton is `2.5 xx 10^(-11)m`. The electricl force of attraction between then will be

Options

A. `2.8 xx 10^(-7)N`
B. `3.7 xx 10^(-7)N`
C. `6.2 xx 10^(-7) N`
D. `9.1xx 10^(-7) N`

Answer

B

Explanation

`F = (9 xx 10^(9) xx 1.6 xx 10^(-19) xx 1.6 xx 10^(-19))/((2.5 xx 10^(-11))^(2)) = 3.7 xx 10^(-7) N`