What will be the angular momentum of an electron, if energy of this electron in `H`-atom is `1.5 eV` (in `J-s`)?

Options

A. `1.05 xx 10^(-34)`
B. `2.1 xx 10^(-34)`
C. `3.15 xx 10^(-34)`
D. `-2.1 xx 10^(-34)`

Answer

C

Explanation

Energy of electron in `H` atom `E_(n) = (-13.6)/(n^(2)) eV`
`rArr - 1.5 = (-13.6)/(n^(2)) rArr n^(2) = (13.6)/(1.5) = 3`
Now angular momentum
`p = n(h)/(2pi) = (3 xx 6.6 xx 10^(-34))/(2 xx 3.14) = 3.15 xx 10^(-34) J xx sec`