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An electron jumps from 5th orbit to 4th ...

An electron jumps from `5th` orbit to `4th` orbit of hydrogen atom. Taking the Rydberg constant as `10^(7)` per meter. What will be the frequency of radiation emitted ?

A

`6.75 xx 10^(12) Hz`

B

`6.75 xx 10^(14) Hz`

C

`6.75 xx 10^(13) Hz`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C

By using `v = RC [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]`
`rArr v = 10^(7) xx (3 xx 10^(8)) [(1)/(4^(2)) - (1)/(5^(2))] = 6.75 xx 10^(13) Hz`
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  2. In the following transitions, which one has higher frequency ?

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  3. An electron jumps from 5th orbit to 4th orbit of hydrogen atom. Taking...

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  8. Energy of the electron in nth orbit of hydrogen atom is given by E(n) ...

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  10. In hydrogen atom, when electron jupms from second to first orbit, then...

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  11. Minimum energy required to takeout the only one electron from ground s...

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  13. When the electron in the hydrogen atom jumps from 2nd orbit to 1st orb...

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