Energy of the electron in `nth` orbit of hydrogen atom is given by `E_(n) =-(13.6)/(n^(2))eV`. The amount of energy needed to transfer electron from first orbit to third orbit is

Options

A. `13.6 eV`
B. `3.4 eV`
C. `12.09 eV`
D. 1.51 eV`

Answer

C

Explanation

For `n = 1, E_(1) = - (13.6)/((1)^(2)) = - 1.51 eV`
and for `n = 3, E_(3) = - (13.6)/((3)^(2)) = - 1.51 eV`
So required energy
`= E_(3) - E_(!) = - 1.51 - (-13.6) = 12.09 eV`