An electron makes a transition from orbit `n = 4` to the orbit `n = 2` of a hydrogen atom. The wave number of the emitted radiations `(R =` Rydberg's constant) will be

Options

A. `(16)/(3R)`
B. `(2R)/(16)`
C. `(3R)/(16)`
D. `(4R)/(16)`

Answer

C

Explanation

Wave number `(1)/(lambda) = R [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))] = R [(1)/(4) - (1)/(16)] = (3R)/(16)`