Ratio of the wavelength of first line of Lyaman series and first line of Balmer series is

Options

A. `1 : 3`
B. `27 : 5`
C. `5 : 27`
D. ` 4 : 9`

Answer

C

Explanation

`(1)/(lambda) = R ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))`
For first line of Lymen series `n_(1) = 1` and `n_(2) = 2`
For first line of Balmer series `n_(2) = 2` and `n_(2) = 3`
So, `(lambda_("Lymen"))/(lambda_("Balmen")) = (5)/(27)`