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The wavelength of Lyman series is...

The wavelength of Lyman series is

A

`(4)/(3 xx 10967) cm`

B

`(3)/(4 xx 10967) cm`1

C

`(4 xx 10967)/(3) cm`

D

`(3)/(4) xx 109767 cm`

Text Solution

Verified by Experts

The correct Answer is:
A
`(1)/(lambda) = R_(H) [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]`. For Lyman series `n_(1) = 1` and `n_(2) = 2`, ltbegt `3.4.` When `n_(2) = 2`, we get `lambda = (4)/(3R_(H)) = (4)/(3 xx 10967) cm`
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