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The ratio of minimum to maximum waveleng...

The ratio of minimum to maximum wavelength in Balmer series is

A

`5 : 9`

B

`5 : 36`

C

`1 : 4`

D

`3 : 4`

Text Solution

Verified by Experts

The correct Answer is:
A

`(1)/(lambda) = R[(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))] rArr (lambda_(min))/(lambda_(max)) = [[(1)/(2^(2)) - (1)/(3^(2))])/[[(1)/(2^(2)) - (1)/(oo)]) = (5)/(9)`
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