Four lowest energy levels of H-atom are ...

Four lowest energy levels of `H`-atom are shown in the figure. The number of possible emission lines would be

`3`

`4`

`5`

`6`

Text Solution

Verified by Experts

The correct Answer is:

Number of possible emission lines `= (n(n - 1))/(2)`
where `n = 4`, Number `= (4(4 - 1))/(2) = 6`

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