The shortest wavelength in the Lyman series of hydrogen spectrum is `912 Å` correcponding to a photon energy of `13.6eV`. The shortest wavelength in the Balmer series is about

Options

A. `3648 Å`
B. `8208 Å`
C. `1228 Å`
D. `6566 Å`

Answer

A

Explanation

In Lyman series `(lambda_(min))_(L) = (1)/(R )` and `(lambda_(min))_(B) = (4)/(R )`
`rArr (lambda_(min))_(B) = 4 xx (lambda_(min))_(L) = 4 xx 912 = 3648 Å`