Home
Class 12
PHYSICS
Energy of the electron in nth orbit of h...

Energy of the electron in `nth` orbit of hydrogen atom is given by `E_(n) =-(13.6)/(n^(2))eV`. The amount of energy needed to transfer electron from first orbit to third orbit is

A

`13.6 eV`

B

`3.4 eV`

C

`12.09 eV`

D

`1.51 eV`

Text Solution

Verified by Experts

The correct Answer is:
C
For `n = 1,E_(1) =- (13.6)/((1)^(2)) =- 13.6 eV`
and for `n=3, E_(3) =- (13.6)/((3)^(2)) =- 1.51 eV`
So required enegry
`= E_(3) - E_(1) =- 1.51 -(-13.6) = 12.09 eV`
Promotional Banner

Topper's Solved these Questions

  • ATOMIC PHYSICS

    A2Z|Exercise Assertion Reason|5 Videos

  • ATOMIC PHYSICS

    A2Z|Exercise Section D - Chapter End Test|30 Videos

  • ATOMIC PHYSICS

    A2Z|Exercise AIPMT/NEET Questions|31 Videos

  • ALTERNATING CURRENT

    A2Z|Exercise Section D - Chapter End Test|30 Videos

  • CURRENT ELECTRICITY

    A2Z|Exercise Section D - Chapter End Test|29 Videos

Similar Questions

Explore conceptually related problems

The energy of an electron in the nth Bohr orbit of hydrogen atom is

Energy of electron in its nth orbit is given by (E_n=-(13.6)/n^2 xxz)ev . Consider a hydrogen atom , find the amount of energy needed to transfer electron from 1st orbit to 3rd orbit:

Total energy of electron in nth stationary orbit of hydrogen atom is

Energy Of Electron In Nth Orbit

The kinetic energy of the electron in the nth orbit of an atom is given by the relation

In the nth orbit, the energy of an electron E_(n)= -( 13.6)/(n^(2)) eV for hydrogen atom. The energy rquired to take the electron from first orbit to second orbit will be

The energy of electron in the nth orbit of hydrogen atom is expressed as E_(n) = (-13.6)/(n^(2))eV . The shortest and longest wavelength of Lyman series will be