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The number of neutrons released when .92...

The number of neutrons released when `._92 U^235` undergoes fission by absorbing `._0 n^1` and `(._56 Ba^144 + ._36 Kr^89)` are formed, is.

A

0

B

1

C

2

D

3

Text Solution

Verified by Experts

The correct Answer is:
D

(d) `._92 U^235 + ._0 n^1 rarr ._92 U^236` and
`._92 U^236 rarr ._56 Ba^144 + ._36 Kr ^89 + 3 ._0 n^1 + Q`.
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The number of neutrons emitteed when ._(92)^(235)U undergoes controlled nulclear fission to ._(54)^(142)Xe and ._(38)^(90)Sr is:

The number of neutrons emitted when ._(92)^(235)U undergoes controlled nuclear fission to ._(54)^(142)Xe and ._(38)^(235)U undergoes controlled nuclear fission to ._(54)^(142)Xe and ._(38)^(90)Sr is:

Calculate the number of neutrons emitted when ._(92)U^(235) undergoes controlled nuclear fission to ._(54)Xe^(142) and ._(38)Sr^(90) .

The number of neutrons that are released on an average during the fission of U^(235) nucleus is

The numberr of neutrons emitted when ""_(92)""^(235)U undergoes controlled nuclear fission to ""_(54)""^(142)Xe and ""_(38)""^(90)Sr is

Find the amount of energy released when 1 atom of Uranium ._(92)U^(235)(235.0439 "amu") undergoes fission by slow neturon (1.0087 "amu") and is splitted into Krypton ._(36)Kr^(92)(91.8973 "amu") and Barium ._(56)Br^(141)(140.9139 "amu") assuming no energy is lost. Hence find the enrgy in kWh , when 1g of it undergoes fission.

The ._(92)U^(235) absorbs a slow neturon (thermal neutron) & undergoes a fission represented by ._(92)U^(235)+._(0)n^(1)rarr._(92)U^(236)rarr._(56)Ba^(141)+_(36)Kr^(92)+3_(0)n^(1)+E . Calculate: The energy released when 1 g of ._(92)U^(235) undergoes complete fission in N if m=[N] then find (m-2)/(5) . [N] greatest integer Given ._(92)U^(235)=235.1175"amu (atom)" , ._(56)Ba^(141)=140.9577 "amu (atom)" , ._(36)r^(92)=91.9263 "amu(atom)" , ._(0)n^(1)=1.00898 "amu", 1 "amu"=931 MeV//C^(2)

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