To generate a power of `3.2` mega watt, the number of fissions of `U^235` per minute is.
(Energy released per fission `= 200 MeV, 1 eV = 1.6 xx 10^-19 J`).

Options

A. `6 xx 10^18`
B. `6 xx 10^17`
C. `10^17`
D. `6 xx 10^16`

Answer

A

Explanation

(a) Number of fission per second
`=("Power output")/("Energy released per fission")`
`=(3.2 xx 10^6)/(200 xx 10^6 xx 1.6 xx 10^-19) = 1 xx 10^17`
rArr Number of fission per minute
`=60 xx 1 xx 10^17 = 6 xx 10^18`.