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The nuclear reaction .^2H+.^2H rarr .^4 ...

The nuclear reaction `.^2H+.^2H rarr .^4 He` (mass of deuteron `= 2.0141 a.m.u` and mass of `He = 4.0024 a.m.u`) is

A

Fusion reaction releasing `24 MeV` energy

B

Fusion reaction absorbing `24 MeV` energy

C

Fission reaction releasing `0.0258 MeV` energy

D

Fission reaction absoring `0.0258 MeV` energy

Text Solution

Verified by Experts

The correct Answer is:
A
(a) Total mass of reactions
=`(2.0141) xx 2 = 4.0282` amu
Total mass of products `= 4.0024 `amu
Mass defect `= 4.0282 "amu" - 4.0024 "amu"`
=`0.0258` amu
`:.` Energy released `E = 931 xx 0.0258 = 24 MeV`.
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