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What is the respective number of alpha a...

What is the respective number of `alpha` and `beta` particles emitted in the following radioactive decay
`._90 X^200 rarr ._80 Y^168`.

A

6 and 8

B

8 and 8

C

6 and 6

D

8 and 6

Text Solution

Verified by Experts

The correct Answer is:
D
(d) `n_alpha = (A - A')/(4) = (200 - 168)/(4) = 8`
`n_beta = 2 n_a - Z + Z' = 2 xx 8 - 90 + 80 = 6`.
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