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An element A decays into element C by a ...

An element `A` decays into element `C` by a two-step process :
`A rarr B + ._2 He^4`
`B rarr C + 2 e overline`
Then.

A

`A` and `C` are isotopes

B

`A` and `C` are isobars

C

`A` and `B` isotopes

D

`A` and `B` are isobars

Text Solution

Verified by Experts

The correct Answer is:
A
(a) `alpha` decay decrease the mass number by `4` and atomic number by `1`. Here atomic number of `C` is same as that of `A`.
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