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In the given nuclear reaction, how many ...

In the given nuclear reaction, how many `alpha` and `beta` particle are emitted `._92 X^235 ._82 Y^207` ?

A

`3 alpha` particles and `3 beta` particle

B

`4 alpha` particle and `3 beta` particle

C

`6alpha` particle and `4 beta` particle

D

`7 alpha` particle and `4 beta` particle

Text Solution

Verified by Experts

The correct Answer is:
D

(d) `n_alpha = (A - A')/(4) = (235 - 207)/(4) = 7`
`n_beta = (2n_alpha - Z + Z') = (2 xx 7 - 92 + 82) = 4`.
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