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In the disintegration series .(92)^(2...

In the disintegration series
`._(92)^(238)U overset rarr (alpha) X overset rarr (beta^(-))._Z^(A)Y` the values of `Z` and `A`, respectively, will be

A

92236

B

88230

C

90234

D

91234

Text Solution

Verified by Experts

The correct Answer is:
D
(d) `._92U^238 rarr ._2He^4 + ._90 X^234 rarr ._(-1)e^0 + ._91 U^234`
Hence, `A = 234, Z = 91`.
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