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In a PNP transistor working as common-ba...

In a `PNP` transistor working as common-base amplifier, current gain is `0.96` and current is `7.2 mA`. The base current is

A

`0.4 mA`

B

`0.2 mA`

C

`0.29 mA`

D

`0.35 mA`

Text Solution

Verified by Experts

The correct Answer is:
C
`alpha=(i_(c))/(i_(e)) =0.96` and `i_(e)=7.2 mA`
`i_(c)=0.96xxi_(e)=0.96xx7.2=6.91mA`
`:. i_(e)=i_(c)+i_(b) implies 7.2=6.91+i_(b) implies i_(b)=0.29 mA`.
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