In a common emitter transistor, the current gain is `80`. What is the change in collector current, when the change in base current is `250 muA`?

Options

A. `80xx250 muA`
B. `(250-80) muA`
C. `(250+80) muA`
D. `250//80 muA`

Explanation

To solve the problem step by step, we will use the relationship between the change in collector current (ΔIc), the change in base current (ΔIb), and the current gain (β) of the transistor.

### Step 1: Understand the relationship
In a common emitter transistor, the current gain (β) is defined as the ratio of the change in collector current (ΔIc) to the change in base current (ΔIb). This can be expressed mathematically as:
\[ \beta = \frac{\Delta I_c}{\Delta I_b} \]

### Step 2: Rearranging the formula
To find the change in collector current (ΔIc), we can rearrange the formula:
\[ \Delta I_c = \beta \times \Delta I_b \]

### Step 3: Substitute the known values
From the problem, we know:
- The current gain (β) = 80
- The change in base current (ΔIb) = 250 μA

Now we can substitute these values into the rearranged formula:
\[ \Delta I_c = 80 \times 250 \, \mu A \]

### Step 4: Calculate the change in collector current
Now, we perform the multiplication:
\[ \Delta I_c = 80 \times 250 = 20000 \, \mu A \]

### Step 5: Convert to a more standard unit
Since 1 mA = 1000 μA, we can convert the change in collector current:
\[ \Delta I_c = 20000 \, \mu A = 20 \, mA \]

### Final Answer
The change in collector current (ΔIc) is **20 mA**.

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