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A common emitter amplifier is designed w...

A common emitter amplifier is designed with `NPN` transistor `(alpha=0.99)`. The input impedence is `1k Komega` and load is `10 Komega`. The voltage gain will be

A

`9.9`

B

`99`

C

`990`

D

`9900`

Text Solution

Verified by Experts

The correct Answer is:
C

Voltage gain `=betaxx` Resistance gain
`beta=(alpha)/(1+alpha)=0.99/((1-0.99))=99`
Resistance gain `=(10xx10^(3))/(10^(3))=10`
`implies` Voltage gain `=99xx10=990`
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