In the `CB` mode of a transistor, when the collector voltage is changed by `0.5` volt. The collector current changes by `0.05 mA`. The output resistance will be

Options

A. `10 k Omega`
B. `20 k Omega`
C. `5 k Omega`
D. `2.5 k Omega`

Answer

A

Explanation

Here `DeltaV_(c)=0.5 V, Deltai_(c)=0.05 mA=0.05 xx10^(-3) A`
Output resistance is given by
`R_(out)=(DeltaV_(c))/(Deltai_(c))=0.5/(0.5xx10^(-3))=10^(4) Omega=10 kOmega`