In the study of transistors as an amplifier, if `alpha=I_(c)//I_(c)` and `beta=I_(c)//I_(b)`, where `I_(c),I_(b)` and `I_(e)` are the collector, base and emitter currents, then

Options

A. `beta=(1-alpha)/(alpha)`
B. `beta=(alpha)/(1-alpha)`
C. `beta=(alpha)/(1+alpha)`
D. `beta=(1+alpha)/(alpha)`

Answer

B

Explanation

As we know `i_(E)=i_(C)+i_(B)`
`implies (i_(e))/(i_(c))=1+(i_(b))/(i_(c)) implies 1/(alpha)=1+1/(beta) implies implies beta=(alpha)/(1-alpha)`.