In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be

Options

A. `10 mV`
B. `0.1V`
C. `1.0V`
D. `10V`

Answer

C

Explanation

`"Voltage gain" ("Output voltage")/("Input voltage")`
`implies V_(out)=V_("in")xx"Voltage gain"`
`implies V_(out)=V_("in")xx"Current gain"xx"Resistance gain"`
`=V_("in")xxbetaxx(R_(L))/(R_(BE))=10^(-3)xx100xx10/1=1V`.