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At 25^(@)C, a solution containing 0.2 ...

At `25^(@)C`, a solution containing `0.2 g` of polyisobutylene in `100 mL` of benzene developed a rise of `2.4 mm` at osmotic equilibrium. Calculate the molecular weight of polyisobutylene if the density of solution is `0.88 g// mL`.

Text Solution

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Height developed `= 2.4 mm`
Osmotic pressure `= h.d.g`
`= (2.4)/(10) xx 0.88 xx 981`
`= 207.187 "dyne" cm^(-2)`
Now `piV = nST`
`207.187 xx 100 = (0.2)/(m) xx 8.314 xx 10^(7) xx 298`
(`R` in erg, `V` in `mL`, using `CGS` system)
`m = 2.39 xx 10^(5)`
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At 25^(@)C a solution containing 0.2g of polyisobutylene in 100 "cc" of benzene, developed a rise of 2.4mm at osmotic equilibrium . Calculate the molecular weight of polyisobutylene if the density of the solution is 0.88g//"cc"

The osmotic pressure of a solution of a synthetic polyisobutylene in benzene was determined at 25^(@)"C" . A sample containing 0.20 g of solute/100 "cm"^(3) of solution developed a rise of 2.4 mm at osmotic equilibrium. The density of the solution was 0.88"g"//"cm"^(3) . What is the molecular weight of the polyisobutylene?

Knowledge Check

  • At 25^(@)C , a solution containing 0.2g of polyisobutylene in 100mL of benzene develpoed a rise of 2.4mm at osmotic equilibrium. Calculate the molecular weight of polyisobutylene if the density of solution is 0.88 g// mL

    A
    `2.39 xx10^(5)g`
    B
    `33.9xx10^(5)g`
    C
    `43.8xx10^(5)g`
    D
    `78.6xx10^(5)g`

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  • 250 mL of a 2 M solution contains 49 g of a substance. Calculate the molecular weight of the compound.

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