At `300 K`, `36 g` of glucose present per litre in its solution has an osmotic pressure of `4.98 bar`. If the osmotic pressure of the solution is `1.52 bar` at the same temperature, what would be its concentration?

Explanation

Given: `O.P. = 4.98 "bar", w = 36 g`
`V = 1 litre` (case I)
`O.P. = 1.52 "bar"`, (case II)
For I: `piV = (w)/(m)S xx T`
`:. 4.98 xx 1 = (36)/(180) xx S xx T` …(1)
For II: `1.52 = C xx S xx T (C = (w)/(m xx V))` ....(2)
By eqs. (1) and (2),
`C = 0.061 molar`