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An aqueous solution of 2 per cent (wt.//...

An aqueous solution of `2` per cent `(wt.//wt)` non-volatile solute exerts a pressure of `1.004` bar at the boiling point of the solvent. What is the molecular mass of the solute?

A

60.43 g

B

41.35 g

C

100.7 g

D

23.22 g

Text Solution

Verified by Experts

The correct Answer is:
B
Given `P_(S) = 1.004 "bar", P^(@) = 1.013 "bar"` (at boiling point `P^(@) = 1.013 "bar" = 1 atm`), `w = 2g`
`:. W = 100 - 2 = 98 g`
From Raoult's law:
`(P^(@)-P_(S))/(P_(S)) = (w xx M)/(m xx W)`
`(1.013-1.004)/(1.004) = (2 xx 18)/(m xx 98)`
`:. m = 41.35 g mol^(-1)`
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