Home
Class 12
CHEMISTRY
What is osmotic pressure of the aq. Solu...

What is osmotic pressure of the aq. Solution of the given solute at `27^(@)C` if depression in freezing point is `0.93^(@)C`? Molal depression constant of water is `1.86K mol^(-1) kg`? Assume molality as molarity.

Text Solution

Verified by Experts

`Delta T = K_(f) xx "Molality", pi = "Molarity" xx ST`
`:. (Delta T_(f))/(pi) = (K_(f))/(ST)` , `(because "Molality = "Molarity")`
`(0.93)/(pi) = (1.86)/(0.0821 xx 300)`
`:. pi = 12.315` atm
Promotional Banner

Topper's Solved these Questions

  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 3B Objectice Problems|1 Videos
  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 9 Advanced Numerical|12 Videos
  • CHEMICAL KINETICS

    P BAHADUR|Exercise Exercise 9|13 Videos
  • ELECTROCHEMISTRY

    P BAHADUR|Exercise Exercise (9) ADVANCED NUMERICAL PROBLEMS|36 Videos

Similar Questions

Explore conceptually related problems

What will be the freezing point of a 0.5 m KCl solution ? The molal freezing point constant of water is 1.86^@C m^(-1) .

What is the molality of solution of a certain solute in a solvent .If there is a freezing point depression of 0.184 ""^(@) C and if the freezing point constant is 18.4 K kg mol^(-1) ?

The freezing point of an aqueous solutions is 272 .93 K . Calculate the molality of the solution if molal depression constant for water is 1.86 Kg mol^(-1)

The freezing point of a 0.05 molal solution of a non-electrolyte in water is [K_(f)=1.86K//m]

The freezing point of a 0.05 molal solution of a non-electrolyte in water is: ( K_(f) = 1.86 "molality"^(-1) )