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The vapour pressure of pure benzene at a...

The vapour pressure of pure benzene at a certain temperature is `640 mm` og `Hg`. A non-volatile non-electrolyte solid weighing `2.175 g` added `39.0 g` of benzene. The vapour pressure of the solution is `600 mm` of `Hg`. What is the molecular weight of solid substance?

Text Solution

Verified by Experts

Given that,
`P^(@) = 640 mm, P_(S) = 600 mm, w = 2.175 g`,
`W = 39.0g, M = 78`
`because (P^(@)-P_(S))/(P_(S)) = (w xx M)/(m xx W)`
`:. (640-600)/(600) = (2.175 xx 78)/(m xx 39)`
`:. m = 65.25`
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