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The vapour pressure of an aqueous soluti...

The vapour pressure of an aqueous solution of glucose is 750 mm of mercury at `100^(@)C`. Calculate the molatlity and mole fraction of solute.

Text Solution

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Given that temperature is `372 K` and `b`. Pt. of `H_(2)O = 373 K`
`:.` Vapour pressure of `H_(2)O = 76 cm`
We have, `(P^(@)-P_(S))/(P_(S)) = ( w xx M)/(mxxW)`
`:.` Molality `= (w)/(mxx W) xx 1000 = (P^(@)-P_(S))/(P_(S)) xx (1)/(M) xx 1000`
`= (760-750)/(750) xx (1)/(18) xx 1000`
`= 0.741 mol//kg` of solvent
Also we have, `(P^(@)-P_(S))/(P^(@)) = (n)/(n+N)`
`:.` Mole fraction `= (P^(@)-P_(S))/(P^(@)) = (760-750)/(760) = (10)/(760) = 0.013`
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