`1.22 g` of benzoic acid is dissolved in acetone and benzene separately. Boiling point of mixture with acetone increase by `0.17^(@)C` and boiling point of mixture with benzene increases by `0.13^(@)C`.
`K_(b) ("acetone")=1.7 K kg "mol"^(-1)`,
Mass of acetone `= 100 g`,
`K_(b) ("benzene")=2.6 k Kg mol^(-1)`,
Mass of benzene `= 100 g`,
Find molecular weight of benzoic acid in acetone and in benzene solution. Justify your answer with structure.

Explanation

To find the molecular weight of benzoic acid in both acetone and benzene solutions, we can use the formula for boiling point elevation, which is given by:

\[ \Delta T_b = K_b \cdot m \]

where:
- \(\Delta T_b\) = boiling point elevation
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